77777 Instructor(s): Field/Matcheva PHYSICS DEPARTMENT PHY 2048

77777 Instructor(s): Field/Matcheva PHYSICS DEPARTMENT PHY 2048
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Instructor(s): Field/Matcheva
PHYSICS DEPARTMENT
Final Exam
PHY 2048
Name (print, last first):
December 13, 2014
Signature:
On my honor, I have neither given nor received unauthorized aid on this examination.
YOUR TEST NUMBER IS THE 5-DIGIT NUMBER AT THE TOP OF EACH PAGE.
(1) Code your test number on your answer sheet (use lines 76–80 on the answer sheet for the 5-digit number).
Code your name on your answer sheet. DARKEN CIRCLES COMPLETELY. Code your UFID number on your
answer sheet.
(2) Print your name on this sheet and sign it also.
(3) Do all scratch work anywhere on this exam that you like. Circle your answers on the test form. At the end of the
test, this exam printout is to be turned in. No credit will be given without both answer sheet and printout.
(4) Blacken the circle of your intended answer completely, using a #2 pencil or blue or black ink. Do not
make any stray marks or some answers may be counted as incorrect.
(5) The answers are rounded off. Choose the closest to exact. There is no penalty for guessing. If you
believe that no listed answer is correct, leave the form blank.
(6) Hand in the answer sheet separately.
Use g = 9.80 m/s2
Axis
R
Axis
Axis
Annular cylinder
(or ring) about
central axis
Hoop about
central axis
R1
Solid cylinder
(or disk) about
central axis
R2
L
R
1
1
I = 2 M(R 12 + R 22 )
I = MR 2
Axis
Solid cylinder
(or disk) about
central diameter
Axis
L
L
I = 2 MR2
Thin rod about
axis through center
perpendicular to
length
Axis
Solid sphere
about any
diameter
2R
R
1
1
Axis
2
1
I = 4 MR2 + 12 ML2
I = 12 ML2
Thin spherical
shell about
any diameter
Axis
R
I = 5 MR2
Hoop about
any diameter
Axis
Slab about
perpendicular
axis through
center
2R
b
a
2
I = 3 MR2
1
I = 2 MR2
1
I = 12 M(a2 + b2)
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PHY2048 Exam 1 Formula Sheet
Vectors
r
r
r
r
ˆ
ˆ
a = axiˆ + a y ˆj + az k b = bxiˆ + by ˆj + bz k Magnitudes: a = a x2 + a y2 + a z2 b = bx2 + by2 + bz2
r
r r
r r r r
r
Scalar Product: a ⋅ b = a xbx + a y by + a z bz Magnitude: a ⋅ b = a b cos θ (θ = angle between a and b )
r r
Vector Product: a × b = (a y bz − a z by )iˆ + (a z bx − a x bz ) ˆj + (a x by − a y bx )kˆ
r
r r r r
r
Magnitude: a × b = a b sin θ (θ = smallest angle between a and b )
Motion
r r
r
Displacement: ∆x = x(t2 ) − x(t1 ) (1 dimension)
∆r = r (t2 ) − r (t1 ) (3 dimensions)
r r
r
r
∆x x(t2 ) − x(t1 )
∆r r (t2 ) − r (t1 )
(1 dim)
Average Velocity: vave =
=
vave =
=
t2 − t1
∆t
∆t
t2 − t1
(3 dim)
Average Speed: save = (total distance)/∆t
r
r
dx(t )
dr (t )
Instantaneous Velocity: v(t ) =
(1 dim)
(3 dim)
v (t ) =
dt
dt
r
r
r
Relative Velocity: v AC = v AB + vBC (3 dim)
r r
r
r
∆v v (t2 ) − v (t1 )
∆v v(t2 ) − v(t1 )
(1 dim)
(3 dim)
Average Acceleration: aave =
=
=
aave =
∆t
∆t
t2 − t1
t2 − t1
r
r
r
dv (t ) d 2 r (t )
dv(t ) d 2 x(t )
(1 dim)
(3 dim)
Instantaneous Acceleration: a (t ) =
a (t ) =
=
=
dt
dt 2
dt
dt 2
Equations of Motion (Constant Acceleration)
v y (t ) = v y 0 + a y t
v z (t ) = v z 0 + a z t
vx (t ) = vx 0 + axt
x(t ) = x0 + vx 0t + 12 axt 2
vx2 (t ) = vx20 + 2ax ( x(t ) − x0 )
y (t ) = y0 + v y 0t + 12 a y t 2
v y2 (t ) = v y20 + 2a y ( y (t ) − y0 )
z (t ) = z0 + v z 0t + 12 a z t 2
v z2 (t ) = v z20 + 2a z ( z (t ) − z0 )
Newton’s Law and Weight
Weight (near the surface of the Earth) = W = mg (use g = 9.8 m/s2)
r
r
Fnet = ma (m = mass)
Magnitude of the Frictional Force
(µs = static coefficient of friction, µk = kinetic coefficient of friction)
Kinetic: f k = µ k FN
(FN is the magnitude of the normal force)
Static: ( f s ) max = µ s FN
Uniform Circular Motion (Radius R, Tangential Speed v = Rω, Angular Velocity ω)
v2
2πR 2π
mv 2
Centripetal Acceleration & Force: a =
Period: T =
= Rω 2 F =
=
= mRω 2
ω
R
v
R
Projectile Motion
(horizontal surface near Earth, v0 = initial speed, θ0 = initial angle with horizontal)
v02 sin(2θ 0 )
Range: R =
g
Max Height:
H=
v02 sin 2 θ 0
2g
Time (of flight):
Quadratic Formula
If:
ax + bx + c = 0
2
− b ± b 2 − 4ac
Then: x =
2a
tf =
2v0 sin θ 0
g
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PHY2048 Exam 2 Formula Sheet
Work (W), Mechanical Energy (E), Kinetic Energy (KE), Potential Energy (U)
r
r
r r
r r
r r
dW
2
1
r→F ⋅d
Kinetic Energy: KE = 2 mv
Work: W = F ⋅ dr   
Power: P =
=
⋅v
F

Cons tan t F
∫rr
dt
2
1
r
r2
r
∫
r
Potential Energy: ∆U = − F ⋅ dr
Work-Energy Theorem: KE f = KEi + W
r
r1
Work-Energy: W(external) = ∆KE + ∆U + ∆E(thermal) + ∆E(internal)
Fx ( x) = −
dU ( x)
dx
Work: W = -∆U
U ( y ) = mgy
Gravity Near the Surface of the Earth (y-axis up): Fy = −mg
Spring Force: Fx ( x) = −kx
U ( x) = 12 kx 2
Mechanical Energy: E = KE + U Isolated and Conservative System: ∆E = ∆KE + ∆U = 0
E f = Ei
Linear Momentum, Angular Momentum, Torque
r
t
r
r
r r dp
r f r
p2
Linear Momentum: p = mv F =
Kinetic Energy: KE =
Impulse: J = ∆p = ∫ F (t ) dt
dt
2m
ti
N
Center of Mass (COM):
M tot = ∑ mi
i =1
r
r
r
dPtot
Net Force: Fnet =
= M tot aCOM
dt
r
1
rCOM =
M tot
N
r
∑ mi ri
i =1
r
1
vCOM =
M tot
N
r
∑p
i
i =1
N
r
r
r
Ptot = M tot vCOM = ∑ pi
i =1
N
Moment of Inertia:
I = ∑ mi ri 2 (discrete) I = ∫ r 2 dm
(uniform)
Parallel Axis: I = I COM + Mh 2
i =1
r
θf
r r dL
Torque: τ = r × F =
Work: W = ∫ τ dθ
dt
θi
r
r
r
r
r
dp
Conservation of Linear Momentum: if Fnet =
= 0 then p = constant and p f = pi
dt
r
r
r
r
r
dL
Conservation of Angular Momentum: if τ net =
= 0 then L = constant and L f = Li
dt
Rotational Varables
r r r
Angular Momentum: L = r × p
Angular Position:
r
d (t ) d 2 (t )
θ (t ) Angular Velocity: ω (t ) = dθ (t ) Angular Acceleration: α (t ) = ω = θ 2
dt
dt
Torque: τ net = Iα Angular Momentum: L = Iω
Arc Length: s = Rθ
Rolling Without Slipping: xCOM = Rθ
L
Power: P = τω
2I
Tangential Acceleration: a = Rα
Kinetic Energy: Erot = 12 Iω 2 =
Tangential Speed: v = Rω
dt
2
vCOM = Rω aCOM = Rα
2
KE = 12 MvCOM
+ 12 I COM ω 2
Rotational Equations of Motion (Constant Angular Acceleration α)
ω (t ) = ω0 + αt
θ (t ) = θ 0 + ω0t + 12 αt 2
ω 2 (t ) = ω02 + 2α (θ (t ) − θ 0 )
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PHY2048 Exam 3 Formula Sheet
Law of Gravitation
m1m2
G = 6.67 × 10 −11 Nm 2 / kg 2
2
r
m1m2
2GM
Potential Energy: U grav = −G
Escape Speed: vescape =
r
R
Tension & Compression (Y = Young’s Modulus, B = Bulk Modulus)
Magnitude of Force: Fgrav = G
Linear:
F
∆L
=Y
A
L
Volume: P =
F
∆V
=B
V
A
Ideal Fluids
Pressure (variable force): P = dF Pressure (constant force): P = F
dA
A
Units: 1 Pa = 1 N/m2
Rm = ρAv = constant (mass flow rate)
Equation of Continuity: RV = Av = constant (volume flow rate)
Bernoulli’s Equation (y-axis up): P1 + 12 ρv + ρgy1 = P2 + 12 ρv + ρgy2 = constant
2
1
2
2
Fluids at rest (y-axis up): P2 = P1 + ρg ( y1 − y2 )
Buoyancy Force: FBuoy = M fluid g
Simple Harmonic Motion (SHM) (angular frequency ω = 2πf =2π/T)
vmax = ωxmax
x(t ) = xmax cos(ωt + φ )
amax = ω 2 xmax
v(t ) = −ωxmax sin(ωt + φ )
a (t ) = −ω 2 xmax cos(ωt + φ ) = −ω 2 x(t )
ω=
Ideal Spring (k = spring constant)): Fx = −kx
k
m
E = 12 mv 2 (t ) + 12 kx 2 (t ) = constant
Sinusoidal Traveling Waves (frequency f = 1/T = ω/2π, wave number k = 2π/λ)
y ( x, t ) = ymax sin(Φ ) = ymax sin(kx ± ωt + φ ) (- = right moving, + = left moving)
Phase: Φ = kx ± ωt
Wave Speed: vwave =
ω
k
=
λ
τ
= λf Wave Speed (tight string): vwave =
T
µ
n = 0,±1,±2,L ∆d = nλ n = 0,±1,±2,L
Interference (Max Destructive): ∆Φ = π + 2πn n = 0,±1,±2,L ∆d = (n + 12 )λ n = 0,±1,±2,L
Interference (Max Constructive): ∆Φ = 2πn
Standing Waves (L = length, n = harmonic number)
v
nv
Allowed Wavelengths & Frequencies: λn = 2 L / n
f n = wave = wave n = 1,2,3L
2L
λn
Sound Waves (P = Power)
Intensity (W/m2): I =
P
A
Isotropic Point Source: I (r ) =
Psource
4πr 2
Speed of Sound in Air (temperature T in Kelvin): vsound (T ) = v0
Speed of Sound: vsound =
T
T0
v0 = 331 m/s
B
ρ
T0 = 273.15 oK
Temperature (Kelvin, Centegrade, Fahrenheit): T(in oK) = T(in oC) + 273.15 T(in oF) = 1.8×T(in oC) + 32
Doppler Shift:
f obs = f S
vsound − vD
(fS = frequency of source, vS, vD = speed of source, detector)
vsound − vS
Change –vD to +vD if the detector is moving opposite the direction of the propagation of the sound wave.
Change –vS to +vS if the source is moving opposite the direction of the propagation of the sound wave.
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1. A motorist drives along a straight road at a constant speed of 40 m/s. At t = 0 she passes a parked motorcycle police
officer, and the officer takes off after her with acceleration a(t) = bt2 , where b is a constant and t is the time. What is
the speed of the police officer (in m/s) when he reaches the motorist?
(1) 160
(2) 200
(3) 240
(4) 80
(5) 100
2. A motorist drives along a straight road at a constant speed of 50 m/s. At t = 0 she passes a parked motorcycle police
officer, and the officer takes off after her with acceleration a(t) = bt2 , where b is a constant and t is the time. What is
the speed of the police officer (in m/s) when he reaches the motorist?
(1) 200
(2) 160
(3) 240
(4) 80
(5) 100
3. A motorist drives along a straight road at a constant speed of 60 m/s. At t = 0 she passes a parked motorcycle police
officer, and the officer takes off after her with acceleration a(t) = bt2 , where b is a constant and t is the time. What is
the speed of the police officer (in m/s) when he reaches the motorist?
(1) 240
(2) 160
(3) 200
(4) 80
(5) 120
4. A rabbit is dashing through the forest. Its position as a function of time is given by ~r(t) = (3 − 5t)î + (3t2 − 2t3 )ĵ, where
position is measured in meters and time in seconds. What is the magnitude of the rabbit’s acceleration (in m/s2 ) at
t = 1 s?
(1) 6
(2) 18
(3) 24
(4) 2
(5) 32
5. A rabbit is dashing through the forest. Its position as a function of time is given by ~r(t) = (3 − 5t)î + (3t2 − 2t3 )ĵ, where
position is measured in meters and time in seconds. What is the magnitude of the rabbit’s acceleration (in m/s2 ) at
t = 2 s?
(1) 18
(2) 6
(3) 24
(4) 2
(5) 32
6. A rabbit is dashing through the forest. Its position as a function of time is given by ~r(t) = (3 − 5t)î + (3t2 − 2t3 )ĵ, where
position is measured in meters and time in seconds. What is the magnitude of the rabbit’s acceleration (in m/s2 ) at
t = 2.5 s?
(1) 24
(2) 6
(3) 18
(4) 2
7. A carnival ride near the surface of the Earth consists of the riders standing
against the inside wall of a cylindrical room with radius R = 6.0 m. The room
spins about the vertical cylinder axis with a constant speed. Once it is up
to speed, the floor of the room falls away. If the cylindrical room completes
16 revolutions per minute, what minimum coefficient of static friction between
the riders and the wall will keep them from dropping with the floor?
(1) 0.582
(2) 0.460
(3) 0.372
(4) 0.288
(5) 32
ω
r
(5) 0.685
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ω
8. A carnival ride near the surface of the Earth consists of the riders standing
against the inside wall of a cylindrical room with radius R = 6.0 m. The room
spins about the vertical cylinder axis with a constant speed. Once it is up
to speed, the floor of the room falls away. If the cylindrical room completes
18 revolutions per minute, what minimum coefficient of static friction between
the riders and the wall will keep them from dropping with the floor?
(1) 0.460
(2) 0.582
(3) 0.372
(4) 0.288
r
(5) 0.685
ω
9. A carnival ride near the surface of the Earth consists of the riders standing
against the inside wall of a cylindrical room with radius R = 6.0 m. The room
spins about the vertical cylinder axis with a constant speed. Once it is up
to speed, the floor of the room falls away. If the cylindrical room completes
20 revolutions per minute, what minimum coefficient of static friction between
the riders and the wall will keep them from dropping with the floor?
(1) 0.372
(2) 0.582
(3) 0.460
(4) 0.288
10. Near the surface of the Earth, a wooden block with mass m = 4 kg is attached
to a string. The string is wrapped around a frictionless pulley with a radius
R = 0.5 m, and rotational inertia I as shown in the figure. The pulley and the
block are initially at rest. If when the system is released and the string begins
to unwind, the tension in the string is 20 N, what is I (in kg·m2 )?
r
(5) 0.685
R I
m
(1) 1.04
(2) 2.35
(3) 3.26
(4) 0.42
11. Near the surface of the Earth, a wooden block with mass m = 4 kg is attached
to a string. The string is wrapped around a frictionless pulley with a radius
R = 0.5 m, and rotational inertia I as shown in the figure. The pulley and the
block are initially at rest. If when the system is released and the string begins
to unwind, the tension in the string is 27.5 N, what is I (in kg·m2 )?
(5) 4.55
R I
m
(1) 2.35
(2) 1.04
(3) 3.26
(4) 0.42
12. Near the surface of the Earth, a wooden block with mass m = 4 kg is attached
to a string. The string is wrapped around a frictionless pulley with a radius
R = 0.5 m, and rotational inertia I as shown in the figure. The pulley and the
block are initially at rest. If when the system is released and the string begins
to unwind, the tension in the string is 30 N, what is I (in kg·m2 )?
(5) 4.55
R I
m
(1) 3.26
(2) 1.04
(3) 2.35
13. Near the surface of the Earth a block of mass M is released from
rest at a height h on a frictionless incline as shown in the figure.
The block slides down the frictionless incline to reach a flat horizontal
surface with a kinetic coefficient of friction µk = 0.5. The block slides
a horizontal distance d and then slides up a frictionless incline and
reaches a maximum height H before sliding back down. If h = d,
what is H?
(1) h/2
(2) 3h/4
(3) h/4
(4) 0.42
(5) 4.55
M
µk
h
d
(4) h
(5) h/3
H
x-axis
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14. Near the surface of the Earth a block of mass M is released from rest
at a height h on a frictionless incline as shown in the figure. The block
slides down the frictionless incline to reach a flat horizontal surface
with a kinetic coefficient of friction µk = 0.25. The block slides
a horizontal distance d and then slides up a frictionless incline and
reaches a maximum height H before sliding back down. If h = d,
what is H?
(1) 3h/4
(2) h/2
(3) h/4
15. Near the surface of the Earth a block of mass M is released from rest
at a height h on a frictionless incline as shown in the figure. The block
slides down the frictionless incline to reach a flat horizontal surface
with a kinetic coefficient of friction µk = 0.75. The block slides
a horizontal distance d and then slides up a frictionless incline and
reaches a maximum height H before sliding back down. If h = d,
what is H?
(1) h/4
(2) h/2
(3) 3h/4
M
µk
h
x-axis
d
(4) h
H
(5) h/3
M
µk
h
d
(4) h
H
x-axis
(5) h/3
16. Near the surface of the Earth a man whose weight at rest is 180 N stands on a scale in an elevator that starts from rest
and accelerates upward with a constant acceleration. If after the elevator has travelled a distance of 10 m its speed is
4 m/s, what is his apparent weight (in N) on the scale in the elevator during his ride?
(1) 194.7
(2) 213.1
(3) 238.8
(4) 165.3
(5) 146.9
17. Near the surface of the Earth a man whose weight at rest is 180 N stands on a scale in an elevator that starts from rest
and accelerates upward with a constant acceleration. If after the elevator has travelled a distance of 10 m its speed is
6 m/s, what is his apparent weight (in N) on the scale in the elevator during his ride?
(1) 213.1
(2) 194.7
(3) 238.8
(4) 165.3
(5) 146.9
18. Near the surface of the Earth a man whose weight at rest is 180 N stands on a scale in an elevator that starts from rest
and accelerates upward with a constant acceleration. If after the elevator has travelled a distance of 10 m its speed is
8 m/s, what is his apparent weight (in N) on the scale in the elevator during his ride?
(1) 238.8
(2) 194.7
(3) 213.1
(4) 165.3
(5) 146.9
19. A race car starts from rest at t = 0 and travels around a circular track of radius R with a constant angular acceleration. If
the magnitude of the tangential acceleration of the car is equal to the magnitude of the radial acceleration (i.e., centripetal
acceleration) of the car at t = 20 s, how long does it take for the race car to complete its first revolution around the
track (in minutes)?
(1) 1.18
(2) 1.77
(3) 2.36
(4) 1.00
(5) 3.00
20. A race car starts from rest at t = 0 and travels around a circular track of radius R with a constant angular acceleration. If
the magnitude of the tangential acceleration of the car is equal to the magnitude of the radial acceleration (i.e., centripetal
acceleration) of the car at t = 30 s, how long does it take for the race car to complete its first revolution around the
track (in minutes)?
(1) 1.77
(2) 1.18
(3) 2.36
(4) 1.00
(5) 3.00
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21. A race car starts from rest at t = 0 and travels around a circular track of radius R with a constant angular acceleration. If
the magnitude of the tangential acceleration of the car is equal to the magnitude of the radial acceleration (i.e., centripetal
acceleration) of the car at t = 40 s, how long does it take for the race car to complete its first revolution around the
track (in minutes)?
(1) 2.36
(2) 1.18
(3) 1.77
(4) 1.00
(5) 3.00
22. A 80-N uniform plank leans at rest against a frictionless wall at an angle θ with the
horizontal as shown in the figure. If θ = 53.13◦ , what is the magnitude of the force
(in N) applied to the plank by the wall?
θ
(1) 30
(2) 25
(3) 20
(4) 80
(5) 120
23. A 80-N uniform plank leans at rest against a frictionless wall at an angle θ with the
horizontal as shown in the figure. If θ = 57.99◦ , what is the magnitude of the force
(in N) applied to the plank by the wall?
θ
(1) 25
(2) 30
(3) 20
(4) 80
(5) 120
24. A 80-N uniform plank leans at rest against a frictionless wall at an angle θ with the
horizontal as shown in the figure. If θ = 63.43◦ , what is the magnitude of the force
(in N) applied to the plank by the wall?
θ
(1) 20
(2) 30
(3) 25
(4) 80
(5) 120
25. A 0.5-kg rubber ball is dropped from rest a height H = 19.6 m above the surface of the Earth. It strikes the sidewalk
below and rebounds up to a maximum height of 4.9 m. If the ball was in contact with the sidewalk for 0.2 seconds, what
is the magnitude of the average force that the sidewalk exerts on the ball during the collision (in N)?
(1) 73.5
(2) 58.8
(3) 49.0
(4) 38.5
(5) 82.2
26. A 0.5-kg rubber ball is dropped from rest a height H = 19.6 m above the surface of the Earth. It strikes the sidewalk
below and rebounds up to a maximum height of 4.9 m. If the ball was in contact with the sidewalk for 0.25 seconds,
what is the magnitude of the average force that the sidewalk exerts on the ball during the collision (in N)?
(1) 58.8
(2) 73.5
(3) 49.0
(4) 38.5
(5) 82.2
27. A 0.5-kg rubber ball is dropped from rest a height H = 19.6 m above the surface of the Earth. It strikes the sidewalk
below and rebounds up to a maximum height of 4.9 m. If the ball was in contact with the sidewalk for 0.3 seconds, what
is the magnitude of the average force that the sidewalk exerts on the ball during the collision (in N)?
(1) 49.0
(2) 73.5
(3) 58.8
(4) 38.5
(5) 82.2
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28. A block slides along a horizontal frictionless surface with speed v. When the
block reaches the point x = 0, two forces with magnitudes F1 = 3x2 N and
F2 = 10 N are applied on the block as shown in the figure. What is the total
work (in J) done on the box if the box travels a distance d from x = 0 to
x = 10 m in the positive x direction?
(1) 900
(2) 273
(3) 75
(2) 900
(3) 75
(2) 900
(3) 273
x=0
(4) 1200
x=d
x axis
x=d
x axis
x=d
x axis
(5) 35
v
F1
F2
x=0
(4) 1200
30. A block slides along a horizontal frictionless surface with speed v. When the
block reaches the point x = 0, two forces with magnitudes F1 = 3x2 N and
F2 = 10 N are applied on the block as shown in the figure. What is the total
work (in J) done on the box if the box travels a distance d from x = 0 to
x = 5 m in the positive x direction?
(1) 75
F2
(4) 1200
29. A block slides along a horizontal frictionless surface with speed v. When the
block reaches the point x = 0, two forces with magnitudes F1 = 3x2 N and
F2 = 10 N are applied on the block as shown in the figure. What is the total
work (in J) done on the box if the box travels a distance d from x = 0 to
x = 7 m in the positive x direction?
(1) 273
v
F1
(5) 35
v
F1
F2
x=0
(5) 35
31. Two stars with masses M1 and M2 orbit with uniform circular motion around their common center of mass. If M1 =
3 × 1030 kg and M2 = 2M1 , and the distance between the stars is 1 × 1010 km, what is the period of their orbit (in
years)?
(1) 257
(2) 472
(3) 727
(4) 315
(5) 578
32. Two stars with masses M1 and M2 orbit with uniform circular motion around their common center of mass. If M1 =
3 × 1030 kg and M2 = 2M1 , and the distance between the stars is 1.5 × 1010 km, what is the period of their orbit (in
years)?
(1) 472
(2) 257
(3) 727
(4) 315
(5) 578
33. Two stars with masses M1 and M2 orbit with uniform circular motion around their common center of mass. If M1 =
3 × 1030 kg and M2 = 2M1 , and the distance between the stars is 2 × 1010 km, what is the period of their orbit (in
years)?
(1) 727
(2) 257
(3) 472
(4) 315
(5) 890
34. Planet Roton, with a mass of 7 × 1024 kg and a radius of 1,500 km, gravitationally attracts a meteorite that is initially
at rest relative to the planet, at a distance great enough to take as infinite. The meteorite falls toward the planet.
Assuming the planet is airless, what is the speed (in km/s) of the meteorite relative to the planet when it reaches the
planet’s surface?
(1) 25.0
(2) 17.6
(3) 14.4
(4) 31.2
(5) 11.6
35. Planet Roton, with a mass of 7 × 1024 kg and a radius of 3,000 km, gravitationally attracts a meteorite that is initially
at rest relative to the planet, at a distance great enough to take as infinite. The meteorite falls toward the planet.
Assuming the planet is airless, what is the speed (in km/s) of the meteorite relative to the planet when it reaches the
planet’s surface?
(1) 17.6
(2) 25.0
(3) 14.4
(4) 31.2
(5) 11.6
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36. Planet Roton, with a mass of 7 × 1024 kg and a radius of 4,500 km, gravitationally attracts a meteorite that is initially
at rest relative to the planet, at a distance great enough to take as infinite. The meteorite falls toward the planet.
Assuming the planet is airless, what is the speed (in km/s) of the meteorite relative to the planet when it reaches the
planet’s surface?
(1) 14.4
(2) 25.0
(3) 17.6
(4) 31.2
37. A block of mass M = 4 kg is at rest on a horizontal frictionless surface and is
connected to an ideal spring as shown in the figure. A 2-gram bullet traveling
horizontally at 290 m/s strikes the block and becomes embedded in the block.
If the bullet-block system comes to rest after compressing the spring a distance
of 4 cm, what is the period (in s) of the subsequent simple harmonic motion
of the system?
(1) 1.73
(2) 2.60
(3) 3.47
(2) 1.73
(3) 3.47
(1) 3.47
(2) 1.73
(3) 2.60
(4) 0.87
40. A cubical metal box with sides of mass M and length L has a square lid also
with mass M and length L. The lid is not attached to the box, however, the
lid and the box form an airtight seal. Near the surface of the Earth, the lid is
held at rest by a steel cable, as shown in the figure. The pressure outside the
box is the atmospheric pressure, Pout = Patm = 101 kPa. The box is partially
evacuated to an inside pressure Pin = 95 kPa. If L = 0.2 m, what is the
maximum mass M (in kg) of the sides of the cubical metal box such that the
box remains at rest and does not fall?
(1) 4.90
(2) 8.98
(3) 13.06
(4) 2.65
41. A cubical metal box with sides of mass M and length L has a square lid also
with mass M and length L. The lid is not attached to the box, however, the
lid and the box form an airtight seal. Near the surface of the Earth, the lid is
held at rest by a steel cable, as shown in the figure. The pressure outside the
box is the atmospheric pressure, Pout = Patm = 101 kPa. The box is partially
evacuated to an inside pressure Pin = 90 kPa. If L = 0.2 m, what is the
maximum mass M (in kg) of the sides of the cubical metal box such that the
box remains at rest and does not fall?
(1) 8.98
(2) 4.90
(3) 13.06
M
(5) 4.95
(4) 2.65
Ideal
spring
v
M
(4) 0.87
39. A block of mass M = 4 kg is at rest on a horizontal frictionless surface and is
connected to an ideal spring as shown in the figure. A 2-gram bullet traveling
horizontally at 290 m/s strikes the block and becomes embedded in the block.
If the bullet-block system comes to rest after compressing the spring a distance
of 8 cm, what is the period (in s) of the subsequent simple harmonic motion
of the system?
Ideal
spring
v
(4) 0.87
38. A block of mass M = 4 kg is at rest on a horizontal frictionless surface and is
connected to an ideal spring as shown in the figure. A 2-gram bullet traveling
horizontally at 290 m/s strikes the block and becomes embedded in the block.
If the bullet-block system comes to rest after compressing the spring a distance
of 6 cm, what is the period (in s) of the subsequent simple harmonic motion
of the system?
(1) 2.60
(5) 11.6
(5) 4.95
Ideal
spring
v
M
(5) 4.95
Pout
Pin
L
L
(5) 18.89
Pout
Pin
L
(5) 18.89
L
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42. A cubical metal box with sides of mass M and length L has a square lid also
with mass M and length L. The lid is not attached to the box, however, the
lid and the box form an airtight seal. Near the surface of the Earth, the lid is
held at rest by a steel cable, as shown in the figure. The pressure outside the
box is the atmospheric pressure, Pout = Patm = 101 kPa. The box is partially
evacuated to an inside pressure Pin = 85 kPa. If L = 0.2 m, what is the
maximum mass M (in kg) of the sides of the cubical metal box such that the
box remains at rest and does not fall?
(1) 13.06
(2) 4.90
(3) 8.98
(4) 2.65
Pout
Pin
L
L
(5) 18.89
43. Stan and Ollie are standing next to a train track. Stan puts his ear to the steel track to hear the train coming. When
the train is 750 m away he hears the sound of the train whistle through the track 2.1 s before Ollie hears it through the
air. If the speed of sound in steel is 5790 m/s, what is the temperature of the air (in ◦ C)?
(1) 9.0
(2) 23.3
(3) 37.9
(4) 18.2
(5) 15.5
44. Stan and Ollie are standing next to a train track. Stan puts his ear to the steel track to hear the train coming. When
the train is 770 m away he hears the sound of the train whistle through the track 2.1 s before Ollie hears it through the
air. If the speed of sound in steel is 5790 m/s, what is the temperature of the air (in ◦ C)?
(1) 23.3
(2) 9.0
(3) 37.9
(4) 18.2
(5) 15.5
45. Stan and Ollie are standing next to a train track. Stan puts his ear to the steel track to hear the train coming. When
the train is 790 m away he hears the sound of the train whistle through the track 2.1 s before Ollie hears it through the
air. If the speed of sound in steel is 5790 m/s, what is the temperature of the air (in ◦ C)?
(1) 37.9
(2) 9.0
(3) 23.3
(4) 18.2
(5) 15.5
46. A large cargo container has a square base with an area of 4 m2 and height
H = 6 m. When empty, it floats on the water (ρwater = 1, 000 kg/m3 ) with
4 meters above the surface of the water and 2 m below the surface as shown
in the figure. The cargo container is being loaded with small 50-kg boxes.
What is the maximum number of boxes the cargo container can hold without
sinking?
(1) 320
(2) 400
(3) 500
(4) 240
4m
2m
(5) 300
47. A large cargo container has a square base with an area of 4 m2 and height
H = 6 m. When empty, it floats on the water (ρwater = 1, 000 kg/m3 ) with
4 meters above the surface of the water and 2 m below the surface as shown
in the figure. The cargo container is being loaded with small 40-kg boxes.
What is the maximum number of boxes the cargo container can hold without
sinking?
(1) 400
(2) 320
(3) 500
(4) 240
4m
2m
(5) 300
48. A large cargo container has a square base with an area of 4 m2 and height
H = 6 m. When empty, it floats on the water (ρwater = 1, 000 kg/m3 ) with
4 meters above the surface of the water and 2 m below the surface as shown
in the figure. The cargo container is being loaded with small 32-kg boxes.
What is the maximum number of boxes the cargo container can hold without
sinking?
(1) 500
(2) 320
(3) 400
(4) 240
4m
2m
(5) 300
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49. What is the maximum total mass (including the mass of the empty balloon) that a spherical helium balloon with a
radius of 1.5 m can lift off the ground? The density of helium and the air are ρHe = 0.18 kg/m3 and ρair = 1.2 kg/m3 ,
respectively.
(1) 14.42 kg
(2) 34.18 kg
(3) 66.76 kg
(4) 10.45 kg
(5) 72.25 kg
50. What is the maximum total mass (including the mass of the empty balloon) that a spherical helium balloon with a
radius of 2.0 m can lift off the ground? The density of helium and the air are ρHe = 0.18 kg/m3 and ρair = 1.2 kg/m3 ,
respectively.
(1) 34.18 kg
(2) 14.42 kg
(3) 66.76 kg
(4) 10.45 kg
(5) 72.25 kg
51. What is the maximum total mass (including the mass of the empty balloon) that a spherical helium balloon with a
radius of 2.5 m can lift off the ground? The density of helium and the air are ρHe = 0.18 kg/m3 and ρair = 1.2 kg/m3 ,
respectively.
(1) 66.76 kg
(2) 14.42 kg
(3) 34.18 kg
(4) 10.45 kg
52. A stationary motion detector on the x-axis sends sound waves of frequency
of 500 Hz, as shown in the figure. The waves sent out by the detector are
reflected off a truck traveling along the x-axis and then are received back at
the detector. If the frequency of the waves received back at the detector is
750 Hz, what is the x-component of the velocity of the truck (in m/s)? (Take
the speed of sound to be 343 m/s.)
(1) −68.6
(2) 38.1
(3) 60.5
(2) −68.6
(3) 60.5
x-axis
(4) 90.3
(5) 68.6
(2) −68.6
(3) 38.1
55. The figure shows two isotropic point sources of sound on the x-axis,
source S1 at x = 0 and source S2 at x = d. The sources emit sound
at the same wavelength λ and the same amplitude A, and they emit
in phase. A point P is shown on the x-axis with 0 < x < d. Assume
that as the sound waves travel to the point P, the decrease in their
amplitude is negligible. If λ = d, at what points P along the x-axis
does maximally destructive interference occur?
x-axis
(4) 90.3
(5) −38.1
(1)
(2)
(3)
(4)
(5)
x = 0.25d and x = 0.75d
x = 0.20d and x = 0.80d
x = 0.15d and x = 0.85d
x = 0.10d and x = 0.90d
Only at x = 0.50d
Truck
Motion
Detector
x-axis
(4) 90.3
(5) −60.5
S1
x=0
Truck
Motion
Detector
54. A stationary motion detector on the x-axis sends sound waves of frequency
of 500 Hz, as shown in the figure. The waves sent out by the detector are
reflected off a truck traveling along the x-axis and then are received back at
the detector. If the frequency of the waves received back at the detector is
350 Hz, what is the x-component of the velocity of the truck (in m/s)? (Take
the speed of sound to be 343 m/s.)
(1) 60.5
Truck
Motion
Detector
53. A stationary motion detector on the x-axis sends sound waves of frequency
of 500 Hz, as shown in the figure. The waves sent out by the detector are
reflected off a truck traveling along the x-axis and then are received back at
the detector. If the frequency of the waves received back at the detector is
400 Hz, what is the x-component of the velocity of the truck (in m/s)? (Take
the speed of sound to be 343 m/s.)
(1) 38.1
(5) 72.25 kg
P
x
S2
x=d
x-axis
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56. The figure shows two isotropic point sources of sound on the x-axis,
source S1 at x = 0 and source S2 at x = d. The sources emit sound
at the same wavelength λ and the same amplitude A, and they emit
in phase. A point P is shown on the x-axis with 0 < x < d. Assume
that as the sound waves travel to the point P, the decrease in their
amplitude is negligible. If λ = 1.2d, at what points P along the x-axis
does maximally destructive interference occur?
(1)
(2)
(3)
(4)
(5)
x=0
S2
P
x=d
x
x-axis
x = 0.20d and x = 0.80d
x = 0.25d and x = 0.75d
x = 0.15d and x = 0.85d
x = 0.10d and x = 0.90d
Only at x = 0.50d
57. The figure shows two isotropic point sources of sound on the x-axis,
source S1 at x = 0 and source S2 at x = d. The sources emit sound
at the same wavelength λ and the same amplitude A, and they emit
in phase. A point P is shown on the x-axis with 0 < x < d. Assume
that as the sound waves travel to the point P, the decrease in their
amplitude is negligible. If λ = 1.4d, at what points P along the x-axis
does maximally destructive interference occur?
(1)
(2)
(3)
(4)
(5)
S1
S1
x=0
S2
P
x=d
x
x-axis
x = 0.15d and x = 0.85d
x = 0.25d and x = 0.75d
x = 0.20d and x = 0.80d
x = 0.10d and x = 0.90d
Only at x = 0.50d
58. A travelling wave on a string is described with the equation y(x, t) = 0.5 cos(5πt − 3πx + 0.5π), where t is in seconds,
and x and y are in meters. How long does it take (in s) for the wave to travel a distance of 10 m along the string?
(1) 6
(2) 9
(3) 12
(4) 3
(5) 15
59. A travelling wave on a string is described with the equation y(x, t) = 0.5 cos(5πt − 3πx + 0.5π), where t is in seconds,
and x and y are in meters. How long does it take (in s) for the wave to travel a distance of 15 m along the string?
(1) 9
(2) 6
(3) 12
(4) 3
(5) 15
60. A travelling wave on a string is described with the equation y(x, t) = 0.5 cos(5πt − 3πx + 0.5π), where t is in seconds,
and x and y are in meters. How long does it take (in s) for the wave to travel a distance of 20 m along the string?
(1) 12
(2) 6
(3) 9
(4) 3
(5) 15
FOLLOWING GROUPS OF QUESTIONS WILL BE SELECTED AS ONE GROUP FROM EACH TYPE
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